0=3n^2+12n+12

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Solution for 0=3n^2+12n+12 equation: 



0=3n^2+12n+12

We move all terms to the left:

0-(3n^2+12n+12)=0

We add all the numbers together, and all the variables

-(3n^2+12n+12)=0

We get rid of parentheses

-3n^2-12n-12=0

a = -3; b = -12; c = -12;
Δ = b2-4ac
Δ = -122-4·(-3)·(-12)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{12}{-6}=-2$

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